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x^2+0.0075x-2.25*10^-4=0
We add all the numbers together, and all the variables
x^2+0.0075x=0
a = 1; b = 0.0075; c = 0;
Δ = b2-4ac
Δ = 0.00752-4·1·0
Δ = 5.625E-5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0075)-\sqrt{5.625E-5}}{2*1}=\frac{-0.0075-\sqrt{5.625E-5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0075)+\sqrt{5.625E-5}}{2*1}=\frac{-0.0075+\sqrt{5.625E-5}}{2} $
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